Hootbro
Well-Known Member
Thanks for the laugh on that oneIt’s mathmagical

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Thanks for the laugh on that oneIt’s mathmagical

There is a lot of deformation going on with tires. There are a lot of TPMS systems that disagree with your conclusion and the mathematics you are using. They use the difference in wheel rotational speed (via the wheel speed sensors) to determine the relative difference in tire pressures. If tire pressure did not affect the rotational speed then these systems would not work. The amount of squish when the tire is loaded does make a difference. The effective tire radius is the distance from the axle to the ground. Regardless, I would dial it in better by putting some miles on an interstate and seeing how accurate it is vs the mile markers over 10 miles or so. Some would use GPS but I don't know if that's better or not.That's fine, you can, but mathematics disagrees with you. The ... outside of the tire still has to make a full revolution every time it goes around (unless severely deflated) so it will still cover basically the same distance.
Huh? The axle being close or far from the ground makes no difference to how fast it spins. The outer circumference of the object is how much distance it covers in 1 revolution and that determines how fast it spins for a given speed. A big oval and a little oval can both spin at 1000 rpms, but the big oval will cover more ground than the little oval over those 1000 rpms and that's all mph is. How much ground is covered by the oval.
Your assumption is the oval's circumference shrinks due to the squish, in reality it stays the same it just becomes more oblong.
Edit: relatively the same I should say, as in with in a few 32nds of an inch or less.
Let's put it another way, I can't air down a 39 to be the same height as a 37 and expect it to spin at the same rpm for a given speed, the 39's oval circumference is just bigger.